Two charges separated by a distance of 1 meter exert a 2-n force on each other. if the magnitude of each charge is doubled, the force on each charge is

8N

Explanation:

coulomb's law is applied in finding the solution to this problem

the law states that "for two point charges separated by a finite distance, the magnitude of force between them id directly proportional to the product of the charges and inversely proportional to the square of the distance between them".

mathematically, F= kq₁q₂/ r²

inital force exerted, F=2N

distance =1m

2=kq₁q₂/ (1)²

2× 1=k × q₁q₂

k=2/q₁q₂

when magnitude of charge is doubled

F¹=kq₁q₂/ r²

new force F¹ = ×

                     =2×2×2

                      =8N

ill do it for 100, also this isnt 80 its 40

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