Physics, 29.08.2019 19:00 graymonky12

Acar starts from rest and accelerates at a constant rate in a straight line. in the first second the car covers a distance of 2.0 meters. how fast will the car be moving at the end of the second second?

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Answer from: eagles2286

The solution would be like this for this specific problem:

Given:

Distance = 2.0 meters

Find:

Vx = ?

Δx = $v_ {0x} t + \frac {1} {2}^ {2} ;$

a = 2 Δx $t^{2} = 2 ( \frac {2m} {1s^{2}} ) = 4
\frac {m} {s^{2}}$

$v_ {x} = v_ {0x} + at = ( 4 \frac {m} {s^{2}}) (2 s) = 8
\frac {m} {s}$

Therefore, the car will be moving 8 m/s at the end of the second second.

To add, the physical vector quantity that both requires magnitude and direction is called velocity. It is also equivalent to a direction of motion and specification of its speed.

Acar starts from rest and accelerates at a constant rate in a straight line. in the first second the

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Acar starts from rest and accelerates at a constant rate in a straight line. in the first second the...

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