The magnitude of the electric force between two protons is 2.3x10-26 n. how far apart are they?
a. 0.022

To solve this problem, we make use of the Coulumb’s law which relates the electrical force to the charges. The formula used in Coulumb’s law is given as:

F = k q1 q2 / r^2

where,

F = electric force = 2.3 *  10^-26 N

k = Coulumb’s constant = 9 * 10^9 N m^2/C^2

q1 = q2 = electric charge of protons = 1.602 * 10^-19 C

r = distance between the two protons

Substituting the given values:

2.3 *  10^-26 N = (9 * 10^9 N m^2/C^2) (1.602 * 10^-19 C)^2 / r^2

r^2 = 0.01 m^2

r = 0.1 m

Therefore the protons are only 0.1 m apart or 10 cm.

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )