How to do the equation p1v1 = p2v2 as an equation layed out like:
p1v1=p2v2
equation
answer
for the question "a sealed of gas at 101,000 pa is expanded, reducing the volume from 0.5m3 to 0.25m3."

An alpha particle with kinetic energy 12.5 mev makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude l = p0 b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.40×10−12 m. (assume that the lead nucleus remains stationary and that it may be treated as a point charge. the atomic number of lead is 82. the alpha particle is a helium nucleus, with atomic number 2.) what is the distance of closest approach?