A negative charge of -4.0 x 10 -6 C and a positive charge of 7.0 x 10 -5 C are separated by 30 cm. What is the force between the two charges?

answer: i don't know the answer good luck

explanation:

this would be about 43%

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j