The volume of air that must be moved by a loudspeaker cone radiating 0.10 W of acoustical power at 50 Hz = cm3. [See Fig. 19.3 in Rossing, page 424.] To displace this volume, the cone of 12-inch (30 cm) diameter speaker would have to move axially
cm.

the answer would most likely be c, because if it's a comical piece of information, it may likely not be true, if it's a site that allows anybody to edit the content, it could mean a five year old is typing the info, and if it's a tv show produced by a celeb, it may have a biased opinion.