Suppose you have 2.5 kg of steam occupying 6.5 m^3 at a pressure of 1.013 x 105^ 5 Pa. When the steam condenses to water, it occupies a volume of 0.55 m^3. If the latent heat of vaporization of water is 2.26x10^6 j/kg , what was the change in the water's internal energy?
Delta T= 0
m = 2.5 kg
Vi= 6.5 m^3
P = 1.013 x 10^5Pa
Vf = 0.55 m^3
Lv = 2.26 x 10^6 j/kg
Q is coming out of the system w is done on the system w
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Suppose you have 2.5 kg of steam occupying 6.5 m^3 at a pressure of 1.013 x 105^ 5 Pa. When the stea...
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