For a concave mirror with the focal length of 3.6 cm, where should a 4.0-cm tall object be placed with respect to the mirror so that it produces a 7.0-cm tall virtual image located 11 cm from the
mirror?

a 2,000 calorie based diet.

i dont have a visual in front of me, but i can you reason to try to get the right one. the graph should look like this, 0 to 6 there is a spike, 12 to 14 there should be a very low point. slight increase in the graph at 12 to 14, and flat 14 to 18

explanation:

the answer is the index of refraction of the second medium is higher. i just took the test.