A baseball batter hits a long fly ball, giving it an initial velocity 45.0° above the horizontal. The ball rises to a maximum height of 14.8 m. An outfielder on the opposing team starts running at 7.60 m/s the instant the ball is hit. Calculate the farthest the fielder can be from where the ball will land so that it is possible for him to catch the ball, i. e. distance between fielder’s original position and lading of the ball.

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j