Physics, 06.05.2021 18:50 millerbe1228
A particle projected at angle teta above the horizontal has a velocity V= (15.5i + 4.8j) m. s-' at time t=0.8 s after launching. (a) What is the maximum height by
the particle? (b) What is the range
of the particle?
Answers: 1
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A particle projected at angle teta above the horizontal has a velocity V= (15.5i + 4.8j) m. s-' at t...
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