A 3.0 kg ball falls from rest. What kinetic energy will it have after 2.5 s? Hint: calculate its speed after 2.5 s.

the answer would be 32*f

see earlier

-4 on

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j