What is the gravitational force between the Earth (mEarth = 5.98 x 1024 kg, rEarth = 6.378 x 106 m)
and a 15,000 kg satellite in Earth’s orbit 575-km above Earth’s surface?


Newtons
I really need help on this! Can someone please help? Thank you!

17.7MN

Explanation:

Given Data

m1 = 5.98 x 10^24 kg

m2= 15,000 kg

R= 6.378 x 10^6 m+575-km

R= 6.378 x 10^3+575*10^3-km

R= 581378m

G = 6.673 x 10-11 N m^2/kg2

This net centripetal force is the result of the gravitational force that attracts the satellite towards the central body and can be represented as

F =GM1M2 / R^2

F =6.673 x 10-11* 5.98 x 10^24*15,000 /  581378^2

F =6.673 x 10^-11* 5.98 x 10^24*15,000 /  581378^2

F= 39.90454*10^13*15,000/  581378^2

F= 598.5681*10^16/338000378884

F= 17709095.5335N

F= 17.7MN

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.