You have two charged objects that are 10 m apart. the force they feel is F. When you bring them closer to a distance of 5 times closer together, by what factor did the force change?

Explanation:

What do you mean by 5 times closer?

If you mean that the new distance is 2 m, then

force is proportional to the inverse of the distance squared.

1/(2²) / 1/(10²) = 25 fold increase

b would be the answer

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft