It is found that the most probable speed of molecules in a gas at equilibrium temperature T2 is the same as the root-mean-square speed of the molecules in this gas when its equilibrium

temperature is T1. Find T2/T1.​

Explanation:

The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:

where,

v = root mean square velocity of molecules:

R = Universal Gas Constant

T = Equilibrium Temperature

M = Molecular Mass of the Gas

Therefore,

For T = T₁ :

For T = T₂ :

Since both speeds are given to be equal. Therefore, comparing both equations, we get:

are there options? cause you ain’t. real specific

3.2x10^7