A light ray in air strikes an oil surface at a 61.0 deg angle, and
moves inside the oil at 38.3 deg.
What is the index of refraction of
the oil?
(Water n = 1.33, Air n = 1.00)
(No Unit)

The index of refraction of the oil is 1.41.

Explanation:

We can find the index of refraction of the oil using Snell's law:

Where:

n₁: is the index of refraction of medium 1 (air) = 1.00

n₂: is the index of refraction of medium 2 (oil) =?

θ: is the angle between the light ray and the medium 1 = 61.0°

α: is the angle between the light ray and the medium 2 = 38.3°

Hence, the index of refraction of the oil is:

Therefore, the index of refraction of the oil is 1.41.

I hope it helps you!                                      

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

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