David is driving a steady 30.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.10 m/s2 at the instant when David passes. Part A How far does Tina drive before passing David

Explanation:

Given

Speed of David car

Tina begins to accelerate after David pass the tina

Suppose it took t time for tina to catch David

Distance traveled by David in t time

Using the equation of motion to get the distance of Tina is

now,

Neglecting

Distance traveled by tina in is

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2

need to see circuit to get time constant