Two resistors A and B are arranged in series in one branch of a parallel arrangement. The other branch contains a single resistor, C. This parallel arrangement is in series with a single resistor D. Describe how you would find the equivalent resistance of the group.

Explanation:

A and B are in series , Total resistance = Ra + Rb

This resistance is in parallel with single resistor C

Equivalent resistance Re = Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )]

Now this combination is in series in single resistance D .

Total resistance = Rd + Re

= Rd + { Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )] }

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