If you put 3.27 moles of an ideal gas in a 50.0 L tank at 35.0°C
what pressure will it create?
(Make sure to put P, V, and T
in the right units.)
(Unit = Pa)

1.65 atm

Explanation:

Applying,

PV = nRT Equation 1

Where P = Pressure, V = Volume, n = number of moles, R = malar gas constant, T = Temperature.

Make P the subject of the equation

P = nRT/V Equation 2

From the question,

Given: n = 3.27 moles, V = 50.0 L, T = 35 °C = (273+35) = 308K

Constant: R = 0.082L.atm/K.mol

Substitute these values into equation 2

P = 3.27(0.082)(308)/(50)

P = 1.65 atm

i think it's 35 meters

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