An arrow is shot at an angle of 75.0o above the horizontal toward a cliff of 60.0-m height. It lands on the cliff 4.00 s later at the very edge of the cliff. Ignore air resistance. What horizontal distance does the archer need to be positioned from the base of the vertical cliff, in order for an arrow, shot with the same speed but with a different angle, to just land on the edge of the cliff at the highest point of the arrow’s flight?