Question Consider a proton moving across an equator of the Earth towards 35° NE-direction, at a speed of 2500 km/s. If
magnetic field at a crossing point is towards 90° direction relative to equator, and has a magnitude of about
0.5 micro-Tesla, how much force would be exerted on a proton?​

Aballoon is rising vertically upwards at a velocity of 10m/s. when it is at a height of 45m from the ground, a parachute bails out from it. after 3s he opens his parachute and decelerates ata a constant rate 5m/s.when. (a) what was the height of the parachutist above the ground when he opened his parachute? (b)how far is the parachutist from the balloon at t=3s? (c)with what velocity does the parachutist hit the ground? (d)after how long does the parachutist hit the ground after his exist from the balloon?