26. A physical science student is performing a thermodynamics experiment in the school laboratory. She takes a 30.0 g ice cube at 0. °C and melts it to water in a beaker over a laboratory burner. She then heats the water to boiling at 100. °C. Finally she boils the water entirely to steam at 100. °C. How much thermal energy was gained by the water during this entire process?

The thermal energy gained by the water during the entire process is 90,372 J

Explanation:

Given;

mass of the ice cube, m = 30 g

latent heat of fusion of ice, L = 334 J/g

specific heat capacity of water, C = 4.184 J/g⁰C

latent heat of vaporization of water, h = 2260 J/g

The thermal energy gained by the water during the entire process is calculated as;

The heat of fusion of the ice at 0⁰C is calculated as;

The heat of capacity of the water from  0⁰C to 100 ⁰C

The heat of vaporization of the steam at 100⁰C is calculated as;

The thermal energy gained by the water during the entire procees;

Qt = 10,020 J  +  12,552 J   +  67,800 J

     = 90,372 J

Therefore, the thermal energy gained by the water during the entire process is 90,372 J

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr