A rod 14.0 cm long is uniformly charged and has a total charge of - 22.0 μC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 36.0 cm from its center.

The direction is toward the negative x axis i.e the Rod

Explanation:

From the question we are told that:

Length

Total charge

Distance

Generally the equation for Electric Field is mathematically given by

Since Magnitude of E is at 36cm away from center

Therefore with Charge Bearing the Negative sign the direction is toward the negative x axis i.e the Rod

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initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft