Imagine you could travel to the moon where the acceleration due to gravity is 1.6 m/s^2. What would be the period of a pendulum that is 1.0 m?
Show your work.

4.9612 s

Explanation:

Applying,

T = 2π√(L/g) Equation 1

Where T = period of the pendulum, L = Lenght of the pendulum, g = acceleration due to gravity of the moon, π = pie.

From the question,

Given: L = 1 m, g = 1.6 m/s²

Constant: π = 3.14

Substitute these values into equation 1

T = 2×3.14×√(1/1.6)

T = 6.28√(0.625)

T = 6.28×0.79

T = 4.9612 s

true is the correct answer

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