The three cables are used to support the 40-kg flowerpot. Determine the force developed in each cable for equilibrium.

The image of the 3 cables used to support the flower pot is not given so i have attached it.

F_ab = 523.2 N

F_ac = 392.4 N

F_ad ≈ 762.7 N

Explanation:

First of all, let's Calculate the sum of forces around the z-axis.

But before then, we need to resolve the distances along the 3 axis to get;

1.5/√(1.5² + 2² + 1.5²) = 0.5145

Thus;

ΣF_z = 0;

(F_ad × 0.5145) - (40 × 9.81) = 0

Where;

(40 × 9.81) is the weight of the flower pot.

F_ad is the force in cable AD

Thus;

0.5145F_ad - 392.4 = 0

F_ad = 392.4/0.5145

F_ad ≈ 762.7 N

Now, let's do the same for the x-axis;

ΣF_z = 0;

Since x = 1.5, just like z was the same 1.5, we will adopt same resolved distance.

F_ac - F_ad(0.5145) = 0

Where F_ac is force in cable AC

F_ac = 762.7 × 0.5145

F_ac = 392.4 N

Lastly, for the y-axis;

ΣF_y = 0;

y is 2 and so, we need to recalculate the resolved distance.

F_ab - F_ad(2/√(1.5² + 2² + 1.5²)) = 0

Where F_ab is the force in cable AB

F_ab = 762.7 × 0.686

F_ab = 523.2 N

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.