Two events are observed in a frame of reference S to occur at the same space point, the second occurring 1.80 s after the first. In a frame S′ moving relative to S, the second event is observed to occur 2.05 s after the first. What is the difference between the positions of the two events as measured in S^?

The difference between the positions of the two events as measured in = 3.53 *10^8 m/s

Explanation:

As we know -

Here,

is the difference between the positions of the two events as measured in S^

And

= 0.547 c

Substituting the given values in above equation, we get -

meter per second

answer; how far out of place which the object finished relative to the starting location;