A long, straight wire lies along the zz-axis and carries a 3.90-AA current in the z z-direction. Find the magnetic field (magnitude and direction) produced at the following points by a 0.600 segment of the wire centered at the origin.

The question is incomplete. The complete question is :

A long, straight wire lies along the z-axis and carries a 3.90-A current in the + z-direction. Find the magnetic field (magnitude and direction) produced at the following points by a 0.600 mm segment of the wire centered at the origin.

A) x=2.00m,y=0, z=0

Bx,By,Bz = ? T

Enter your answers numerically separated by commas.

B) x=0, y=2.00m, z=0

C) x=2.00m, y=2.00m, z=0

D) x=0, y=0, z=2.00m

Solution :

The expression of the magnetic field using the Biot Savart's law is given by :

a). The position vector is on the positive x direction.

The magnetic field is  

The magnetic field is  

b). The position vector is in the positive y-direction.

The magnetic field is

The magnetic field is  

c). The position vector is :

The magnetic field is

The magnitude of the magnetic field is :

Therefore, the magnetic field is

d).  The position vector is in the positive y-direction.

The magnetic field is

   = 0 T

The magnetic field is (0, 0, 0)

are you like autistic or something?

xd

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)