Two workers are sliding 450 kg kg crate across the floor. One worker pushes forward on the crate with a force of 380 NN while the other pulls in the same direction with a force of 230 NN using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor

The coefficient of kinetic friction on the floor is 0.138

Explanation:

Given;

mass of the crate, m = 450 kg

force applied by the first worker, F₁ = 380 N

force applied by the second worker in the same direction as the first worker, F₁ = 230 N

frictional force opposing the motion of the box = -

Apply Newton's second law of motion;

∑F = ma

If the crate slides with constant speed, acceleration is zero (0).

Therefore, the coefficient of kinetic friction on the floor is 0.138

as technology advances, new experiments often expose problems in accepted theories. c

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-lavira: )

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge