Se dinamita una roca la cual se fragmenta en tres partes: m1= 12kg, m2= 25 kg y m3= 8 kg. Las dos primeras salen disparadas formando entre sí un ángulo de 50grados, con rapideces v1= 20 m/s y v2= 14 m/s. Determina: magnitud y dirección de la velocidad y la cantidad de movimiento del tercer fragmento: Utiliza un sistema de coordenadas rectangulares.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

The genes are more on the side of.. b nature

F= (mass)(acceleration) = mam = 0.25 kgvi = 16 m/st = 2 svf = 0 m/s (since it was put to stop)a=(vf-vi)/ta=(0-16)/2a = 8 m/s^2 (decelerating)f = ma = (0.25 kg)(8 m/s^2)f = 2 nhope this !