A lumberjack is trying to drag a small tree that he cut down. If the static coefficient of friction of the tree on the ground is 0.5 and the tree weighs 430
N, what is the minimum amount of horizontal force that he will need to apply
so that the tree will start moving?
A. 215 N
B. 430 N
C. 365 N
D. 500 N

A

Explanation:

weight of the tree =normal force

Horizontal force =coefficient of friction x Fnormal

0.5×430=215

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

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