A ball is thrown with an initial velocity of 30.0 m/s and makes an angle of 30.0° with the ground. Find the

A. Horizontal Distance

B. Maximum Height

C. Total Time The Ball is Traveling​

Statements imply it is thrown with 30cos30° horizontally and 30sin30° vertically.

Vertically:

Total time taken = 2(v - u)/a = 0 - 30sin30°)/(-g) = 30/g

Therefore, it would travel 30/g sec in horizontal direction also. Horizontally

Distance = speed x time = 30cos30° (30/g) = 450√3 /g

If g = 10, distance is 45√3 m.

Vertically,

Distance = speed x (time of flight/2)

Distance = 30sin30° x (30/g)/2 = 90 m.

Time taken = 30/g = 3 sec

i think the answer is a and b

i wish you luck