Find the resultant of these two forces : 2.00 x 10^2 N due east and 4.00 x 10^2 N 30.0 degree north of west

If two vectors are represented both in magnitude and direction by the two adjacent sides of a triangle taken in an order, then their resultant is given by the third side taken in the reverse order.

Resultant vector :

                         R = sqrt of A^2 + B^2 + 2ABcosθ

given :

          A = 200 units

          B = 300 units

          θ = 30 degrees

∴ R = sqrt of 200^2 + 300^2 + 2(200)(300)cos35

the answer is 477.805656

what is the question because that is not a question.

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.