A 32.0 kg cart is at rest on a frictionless, horizontal surface. The cart experiences an unbalanced force, causing the cart to accelerate at a rate of +5 m/s2.
A student claims that the normal force acting on the cart is equal in magnitude to the weight of the cart. Is the student correct?
A
Yes, the student is correct because the normal force is the equal and opposite reaction to the cart’s weight being applied on a surface, as described in Newton’s Third Law of Motion.
B
Yes, the student is correct because the normal force is directly proportional to the mass of the cart, as described in Newton’s Second Law of Motion.
C
No, the student is incorrect because the normal force is not the equal and opposite reaction to the cart’s weight being applied on a surface, as described in Newton’s Third Law of Motion.
D
No, the student is incorrect because the normal force is inversely proportional to the mass of the cart, as described in Newton’s Second Law of Motion.
Answers: 1
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1. explain how you calculate the net force in any direction on the box. 2. suppose an upward force of 15n is added to the box. what will be the net vertical force on the box? 3. what force could be applied to the box to make the net force in the horizontal direction zero? explain. 4. suppose a force of 25n to the right is added to the box. what will be the net force to the right?
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