The following diagram represents Neptune, Uranus, and the Sun in a straight line. Neptune is 1.63 x 1012 meters from Uranus. Calculate the magnitude of the interplanetary force of attraction between Uranus and Neptune at this point. [Show all work, including the equation and substitution with units.] Equation: Fg=6.67x10-11 x m1 x m2 divided by r2

Point charges q1=+2.00μc and q2=−2.00μc are placed at adjacent corners of a square for which the length of each side is 1.50 cm . point a is at the center of the square, and point b is at the empty corner closest to q2. take the electric potential to be zero at a distance far from both charges. part a what is the electric potential at point a due to q1 and q2? express your answer with the appropriate units.