In an open pipe 80 cm long you find the 5th harmonic to be 1062.5 Hz, what would happen to the frequency if you covered the end of the pipe?

what type of charge does it have? negative

the strength of the electric field on the point charge= n/c

the electric field is given by

e=

q=6μc= 6 x 10⁻⁶c

r=100 m

e=

e=5.4 n/c

so the electric field on the point charge= 5.4n/c