Derive v2=u²+2as
derive

From 1st equation of motion,

V = U +AT

Therfore, V - U = AT …eq 1

We know that

S = (U + V / 2 )×T

∴ S/T = U + V / 2

∴U + V = 2×S/T

∴ U + V = 2S / T … eq2

So Substituting eq1 and eq2,

(V - U ) (V + U ) = AT ×2S/T

∴V² - U² = 2AS.

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im doing peak rn so sry if its wrong