The element radon is at the opposite end of the range, with the lowest specific heat of all naturally occurring elements. Radon's specific heat is 94 J/kg°C. If the temperature of a 0.34 kg sample of radon is to be raised by 25°C, how much energy will have to be added to the radon?

Explanation:

Q = mc∆T

= (0.34 kg)(94 J/kg-°C)(25°C)

= 799 J

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft