5) A 2.0-meter length of copper wire is connected across a potential difference of 24 millivolts.
The current through the wire is 0.40 ampere. The same copper wire at the same temperature
Is then connected across a potential difference of 48 millivolts. The current through the wire
is
A)
0.20 A
B)
0.80 A
C)
1.6 A
D)
0.40 A

The current through the wire is equal to 0.8 A.

Explanation:

Given that,

The length of a copper wire = 2 m

Potential difference = 24 mV

The current through the wire is 0.40 A.

The new potential difference is 48 mV.

We need to find the current through the wire.

As the potential difference is doubled for second wire. So the new current will be :

I' = 2I

= 2 × 0.4

= 0.80 A

So, the current through the wire is equal to 0.8 A.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow