The hull of a sunken boat, laying on the seabed, is 9 m below the surface of the sea, where the sea water has an average density of 1,025 kg/m3. The hull’s surface area is 12 m2. What is the total force exerted by seawater on the hull?Required to answer. Single line text.

1084860 N

Explanation:

Applying,

P = ρgh Equation 1

Where P = pressure, ρ = density, h = height, g = acceleration due to gravity.

From the question,

Given:  ρ = 1025 kg/m³, h = 9 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

P = (1025)(9)(9.8)

P = 90405 N/m²

Also,

P = F/A Equation 2

Where, F = Force, A = Area.

Make F the subject of the equation

F = PA Equation 2

Given: A = 12m²

F = 12(90405)

F = 1084860 N

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )