Acircuit consist of three resistor in series one of 3 ohm, one of 7 ohm , one of 10 ohm battery of emf 12volt and neglible internal resistance is connected circuit what is size of circuit supply

0.6 A

Explanation:

Applying,

I = E/(R'+r) Equation 1

Where I = curent or circuit supply, R'= equivalent external resistance, r = internal resistance.

From the question,

Given: E = 12 Volt,

IF the three resistors are connected in series, R' = (3+7+10) ohm = 20 ohm,

r = neglible.

Substitute these values into equation 1

I = 12/(20)

I = 0.6 A

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

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