Charge of uniform density (80 nC/m3) is distributed throughout a hollow cylindrical region formed by two coaxial cylindrical surfaces of radii 1.0 mm and 3.0 mm. Determine the magnitude of the electric field at a point which is 2.0 mm from the symmetry axis.

Magnitude of the electric field at a point which is 2.0 mm from the symmetry axis is 18.08 N/C.

Explanation:

Given: Density = 80 (1 n = m) =

= 1.0 mm (1 mm = 0.001 m) = 0.001 m

= 3.0 mm = 0.003 m

r = 2.0 mm = 0.002 m (from the symmetry axis)

The charge per unit length of the cylinder is calculated as follows.

Substitute the values into above formula as follows.

Therefore, electric field at r = 0.002 m from the symmetry axis is calculated as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that magnitude of the electric field at a point which is 2.0 mm from the symmetry axis is 18.08 N/C.

a.metals can become magnetic if they have many spinning electrons that create magnetic fields.d.only some metals are attracted by magnets; these metals are called ferromagnetic.

d.wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current.