A string is wrapped several times around the rim of a small hoop with a radius of 0.0800 m and a mass of 0.170 kg. The free end of the string is held in place and the hoop is released from rest . Calculate the angular speed of the rotating hoop after it has descended 0.750 m

Gravity bc it’s gravity

Ibelieve the answer is d. macula  hope my answer has you : )

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.