A car's speed changes from 10m/s to 35m/s in 15.0s along a straight road while moving in one way. Find the magnitude of the acceleration of the car during this period.​

1.67 m/s²

Explanation:

Applying,

a = (v-u)/t Equation 1

Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.

From the question,

Given: v = 35 m/s, u = 10 m/s, t = 15.0 s

Substitute these values into equation 1

a = (35-10)/15

a = 25/15

a = 1.67 m/s²

Hence the acceleration of the car is 1.67 m/s²

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

what is the question because that is not a question.