A bus moves to right with velocity 10.0 m/s, covers 5.0 km in 3.5 min. Find the velocity of the bus at the end of this time interval
1. 57.61 m/s to the right
2. 7.14 m/s to the left
3. 4.32 m/s to the right
4. 37.61 to the right ​

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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