A package of mass m is released from rest at a warehouse loading dock and slides down a 3.0-m-high frictionless chute to a waiting truck. Unfortunately, the truck driver went on a break without having removed the previous package, of mass 2m, from the bottom of the chute. Suppose the packages stick together. What is their common speed after the collision

The speed of combined package after the collision is .

Explanation:

mass of first package = m

height , h = 3 m

mass of second package = 3 m

let the speed of first package is u as it strikes with the second package.

Use the third equation of motion

Let the velocity of combined package after the collision is v.

Use the conservation of momentum

i think if it were me i whould divide 300 dide 15

step-by-step explanation: