If a block of a horizontal oscillator moving in the positive direction takes 1 (s) to move from the equilibrium position (x=0) to the positive maximum displacement (x=+A) ,Then the period T of this simple harmonic motion is equal to:​

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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C. the electric current passes from the slip rings, through the brushes, and to the collection device.