CA Stone of mass 40kg is released from A Catapult whose rubber has been stretched
through 5mm. If the stiffness of the rubber
is 20 Nm^1 CALCULATE the velocity with which
the stone Leaves the Catapult!​

v = 3.53x10⁻³ m/s.

Explanation:

We can find the velocity of the rock by energy conservation:

Where:

i is for initial and f is for final

k: is the stiffness of the rubber = 20 N/m

x: is the distance of the rubber compression = 5 mm = 0.005 m

m: is the mass of the stone = 40 kg

v: is the velocity =?

Hence, the velocity is:

Therefore, the velocity with which the stone leaves the catapult is 3.53x10⁻³ m/s.

I hope it helps you!  

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation: