How fast much an 816kg Volkswagen travel to have the same momentum as (a) a 2650kg Cadillac going 16.0 km/h? (b) a 9080-kg truck also going 16.0 km/hr?

Explanation:

(a) The momentum of a 2650kg Cadillac going 16.0 km/h or 4.44 m/s is :

p = 2650 kg × 4.44 m/s

= 11766 kg-m/s

(b) The momentum of a 9080-kg truck also going 16.0 km/hr or 4.44 m/s is :

p =mv

= 9080-kg × 4.44 m/s

= 40315.2 kg-m/s

If p = 11766 kg-m/s, velocity is :

If p = 40315.2 kg-m/s, velcocity is :

Hence, this is the required solution.

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?