In serving, a tennis player accelerates a 59 g tennis ball horizontally from rest to a speed of 34 m/s Assuming that the acceleration is uniform when the racquet is applied over a distance of 0.36 m, what is the magnitude of the force exerted on the ball by the racquet

The magnitude of the force exerted on the ball by the racquet is 94.73 N.

Explanation:

The force exerted on the ball is the following:

Where:

m: is the mass of the ball = 59 g

a: is the acceleration

The acceleration of the ball can be found with the following kinematic equation:

Where:

d: is the distance = 0.36 m

: is the final speed = 34 m/s

: is the initial speed = 0 (it start from rest)

Hence, the acceleration is:

Finally, the force is:

Therefore, the magnitude of the force exerted on the ball by the racquet is 94.73 N.                                

I hope it helps you!                                                              

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)