How large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius 110 m at a speed of 101 km/h

The magnitude of static friction is

f = mv ²/r

(i.e. the net force acting on the car parallel to the road points toward the center of the curve)

while the net vertical force must be

∑ F = n - mg = 0

because the car is otherwise in equilibrium. Then

==>   n = mg

==>   f = µn = µmg = mv ²/r

==>   µ = v ²/(rg)

We have

v = 101 km/h ≈ 28.1 m/s

r = 110 m

g = 9.80 m/s²

so that

µ = (28.1 m/s)² / ((110 m) g) ≈ 0.730

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

the motion of a pendulum is a classic example of mechanical energy conservation. a pendulum consists of a mass (known as a bob ) attached by a string to a pivot point. as the pendulum moves it sweeps out a circular arc, moving back and forth in a periodic fashion.