A fan that is rotating at 960 rev/s is turned off. It makes 1500 revolutions before it comes to a stop. a) What was its angular acceleration(assuming it was constant)

α = 1930.2 rad/s²

Explanation:

The angular acceleration can be found by using the third equation of motion:

where,

α = angular acceleration = ?

θ = angular displacement = (1500 rev)(2π rad/1 rev) = 9424.78 rad

ωf = final angular speed = 0 rad/s

ωi = initial angular speed = (960 rev/s)(2π rad/1 rev) = 6031.87 rad/s

Therefore,

α = - 1930.2 rad/s²

negative sign shows deceleration

higher potential

explanation:

because it is in a high speed so it must move into a of high potential